Strange question.The distance from the center of the Earth is increased twice, the force of gravity( and hence the acceleration of gravity) is reduced by 4 times.Divide by 4 and 9.8 obtain 2.65 m / s2.It is in a first approximation.Excluding centrifugal and buoyancy forces.
Perhaps this is the assumption that the Earth - the point?Because the distance a small, half the diameter of Earth. - More than a year ago In this story, the most remarkable thing is that the gravitational field of an ideal sphere of constant density is exactly the same with the gravitational field of a material point having the mass of the ball and located in its center.That is, at an altitude of 600 m free fall acceleration - 0.01% less. - More than a year ago Thank you.I used this, of course, knew( When taking exams in physics), but forgot:) . - More than a year ago The great thing is that if the density of the ball is not constant, but at least the centrally symmetric - then its gravitational field is still the same as in point. - More than a year ago The Earth is symmetric only the kernel.And all sorts of Kursk anomaly - a trifle has an impact on g only in the immediate vicinity of ε:) . - More than a year ago